A current of 0.2ampere is passes through a solution of CuSO_4 for 10 m – InterviewSolution

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1.	A current of 0.2ampere is passes through a solution of CuSO_4 for 10 minutes calculate the man of Cu deposited on the cathode.
Answer» Solution :`W=Q L t` `W=E/96500 TIMES I t` `=(31.75 times 0.2 times 10 times 60)/96500` `=0.03948 G`

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