1.

A current of 0.5 A in the primary coil of a transfomer is reduced to zero at a uniform rate in 0.1 second. If the coefficient of mutual inductance is 3H, what is the emf induced in the secondary coil and charge in the magnetic flux per turn in the secondary coil if it has 50 turns?

Answer»

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Solution :DATA: `(dI_(P))/(DT) = -(0.5a)/(0.1 s) = -5A//s, M=3H, N_(s)= 50`
(i) The emf induced in the secondary COIL
`=-M(dI_(P))/(dt) = -3 xx (-5) = 15 V`
(ii) `E_(S) = -N_(S)(dPhi_(S))/(dt)`
`THEREFORE dPhi_(S) = -(E_(s)dt)/(N_(S)) = -(15 xx 0.1)/50 = -0.03` Wb
This gives the change in the magnetic flux per turn in the secondary coil.


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