1.

A current of 0.5 amperes is passed for 30 minute through a voltmeter containing CUSO_4 Solution. Find the weight of Cu deposited

Answer»

3.18 g
0.318 g
0.296 g
0.150 g

Solution :`W=ZxxIxxt`
`Z=(E)/(96500)=(Mol.wt.//2)/(96500)`[for copper, E=mol. Wt/2]
Given, CURRENT passed=0.5A
time=30mins=`30xx60s`
`W=(63.5)/(2)xx(1)/(96500)xx0.5xx30xx60=0.296g`.


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