1.

A current of 1.0 A was passed for 2 hr through a solution of cuprocyanide and 0.3745 g of copper was deposited on the cathode. Calculate the current efficiency for the copper deposition. (Cu-63.5)

Answer»

`79%`
`39.5%`
`63.25%`
`63.5%`

SOLUTION :m(THEORETICAL)`=(63.5xx0.1xx7200)/(96500)=0.4738g`
`THEREFORE%` EFFICIENCY `=(0.3745)/(0.4738)xx100=79%`


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