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A current of 10.0A is passed through 1.0L of 1.0M HCl solution for 965 seconds, pH of the solution at the end of the experiment is:- |
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Answer» 0 `H^(+)+e^(-)to(1)/(2)H_(2)` 1 FARADAY PRODUCES 0.5 mole of `H_(2)` `(965xx10)/(96500)` faraday produces`=(0.5xx965xx10)/(96500)` `=0.05` mole of `H_(2)` `0.05` mole of `H_2` contains 0.1 mole H. `therefore0.9` mole `H^+` left in solution. `pH=-log[0.9]=0.125`. |
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