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A current of 100 A flows in a conical copper with dimensions as shown in Fig 26.8. Find the current density and electric field intensity at the end faces of the conductor

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SOLUTION :The diameter of an arbitrary cross section of the conductor a distance X from the minimum cross section is y=a+z (D-a)/L. The current density and the field strength in an arbitrary cross section are `i=i/S=(4i)/(PI y^2), E=pl =(4pi)/(4pi y^2)`


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