1.

A current of 2.0A passed for 5 hours through a molten metal salt deposits 22.2 g of metal (At wt.=177). The oxidation state of the metal in the metal salt is

Answer»

`+1`
`+2`
`+3`
`+4`

Solution :`Q=2xx5xx60xx60=36000C`
THUS, 36000C deposit METAL=22.2 G
`therefore96500C` will deposit metal
`=(22.2)/(36000)xx96500g=59.5g`
Thus, EQ. wt. of the metal=59.5
Valency or ox. State=At. Wt./Eq. wt.
`=177//59.3=3`.


Discussion

No Comment Found