InterviewSolution
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InterviewSolution
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A current of `2.50` A passing through a heating coil immersed in `180 g` of paraffin (specific heat capacity `2.00 J g^(-1) K^(-1)`) contained in a `100 g` calorimeter (specific heat capacity `0.400 J g^(-1) K^(-1)`) raise the temperature from `5^(@)C` below room temperature to `5^(@)C` above room temperature in `100 s`. the reading of the voltmeter connected across the heating coil isA. `8.0 V`B. `16.0 V`C. `24.0 V`D. `32.0 V` |
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Answer» Correct Answer - B Power `= ("heat supplied")/("Time")` `=(m_(1)s_(1)Delta theta+m_(2)s_(2)Delta theta)/(T)` `(180g xx 2 Jg^(-1)K^(-1)xx10K)+` `=((100gxx0.4Jg^(-1)K^(-1)xx10K))/(100s)` `=40W` `=VI = 40 W rArr V = (4.0)/(2.5) = 16.0V`. |
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