1.

A current of 2.6 ampere was passed through CuSO_(4) solution for 380 sec . The amount of Cu deposited is (atomic mass of Cu 63.5)

Answer»

`0.3250 G`
`0.635` g
`6.35` g
`3.175 g`

Solution :`W = (E xxi XX t)/(96500) = (63.5 xx 2 .6 xx380)/(2 xx 96500) = 0.325` g


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