A current of 2 A flows through a 2Omegaresistor when connected across a battery. The same batterysupplies a current of 0.5 A when connected across a 9 Omegaresistor. The internal resistance of the battery is

A current of 2 A flows through a 2Omegaresistor when connected across

1.	A current of 2 A flows through a 2Omegaresistor when connected across a battery. The same batterysupplies a current of 0.5 A when connected across a 9 Omegaresistor. The internal resistance of the battery is
Answer» `1Omega` `2OMEGA` `1/3 OMEGA` `1/4 Omega` Solution :We KNOW that `I = (epsi)/(R + r)` ` therefore 2 = (epsi)/(2 + r) " and " 0.5 = (epsi)/(9 + r) rArr r = 1/3 Omega`

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A current of 2 A flows through a 2Omegaresistor when connected across a battery. The same batterysupplies a current of 0.5 A when connected across a 9 Omegaresistor. The internal resistance of the battery is

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