A current of 2 ampere was passed through solutions of CuSO_(4) and AgN – InterviewSolution

InterviewSolution

1.	A current of 2 ampere was passed through solutions of CuSO_(4) and AgNO_(3) in series . 0.635 g of copper was deposited . Then the weight of silver depositedwill be
Answer» `0.59` g `3.24` g `1.08` g `2.16` g Solution :A/c. to FARADAY's `II^(ND)` law or `(0.635)/(63.5//2) = (w_(AG))/(108)` `therefore W_(Ag)= 2.16 g `

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