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A current of 2A is increased at a rate of 4 A/s through a coil of inductance 2H. The energy stored in the inductor per unit time is (A) 2 J/s(B) 1 J/s(C) 16 J/s(D) 4 J/s |
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Answer» Correct option is (C) 16 J/s Energy stored per unit time = \(Li\frac{di}{dt}\) = 2 (2) (4) = 16 J/s. |
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