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A current of 4 A flows in a coil when connected to a 12 V dc source. If the same coil is connected to a `12 V, 50 rad s^(-1)` ac source, a current of 2.4 A flows of the coil in the circuit. The inductance of the coil isA. 0.02HB. 0.04HC. 0.08HD. 1.0H |
Answer» Correct Answer - C When dc is applied , `I=V/R i.e, R=12/4 = 3 Omega` and when ac is applied , `Z+V/I = ((12)/(2.4))= 5 Omega` `R^(2) + X_(L)^(2) = 5^(2) (as Z= sqrt(R^(2)+X_(L)^(2)))` so, `X_(L)^(2) = 5^(2)-R^(2) = 5^(2)-3^(2)=4^(2), i.e. X_(L) = 4 Omega` but as , `X_(L) = omega L , L (X_L) /(omega) = (4)/(50)= 0.08 H`. |
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