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A current of 5.0 A is passed through a 100L aqueous solution of sodium soccinate for 4.0h. The gases produced at anode are collected separately at 25^(@)C and 1.0 atm pressure. Find thevolume of gases. Also find the pH of solution at the end of electrylysis . ( Assume that at the start of electrolysis, pH of solution is 7.0 at 25^(@)C) |
Answer» Solution :At anode `:` `2F=1mol` of`(CH_(2)=CH_(2)+2mol of CO_(2))` `2F=3 mol `of gases NUMBER of Faradays`=(5xx4xx3600)/(96500)=0.746F` `({:(mol es of gases),(at 25^(@)C and 1 atm):})=(3)/(2)xx0.746~~1.12` `=1.12xx24.48L` `=27.4L` At cathode `:` `2H_(2)O+2e^(-) rarr 2overset(-)(O)H+H_(2)uarr` 2F=2mol `of `OVERSET(-)(O)H` `0.746F=0.746` mol of `overset(-)(O)H` `[overset(-)(O)H]=(0.746Eq)/(100L)=0.007746M` or `N` `:. pOH=2.13` `pH=14-pOH=11.87` |
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