1.

A current of 5 amp is passed through a solution of NaCl for 3.25 hrs . The weight of NaOH formed is

Answer»

6.50 G
17.25g
24.25 g
`13.0` g

SOLUTION :1gM.mass NaCl`-=`1 g M. mass of NaOH
58.5 NaCl `-=` 40 g NaOH
`:.1 F= 96500` Celectricity passed `-= 1g` eq. mass NaOH FORMED
`-=40`g of NaOH formed
`:.Q=I xxt=5xx3.25xx60xx 60C=Wt. of NaOH`
`:. 58500 C =Wt.of NaOH`
Wt.of `NaOH=(ixxtxxR)/F=(58500xx 40)/96500=24.25 g`


Discussion

No Comment Found

Related InterviewSolutions