1.

A current of 9.65 A is passed for 3 hours between nickel electrodes in 0.5 L of a 2 M solution of Ni(NO_3)_2. The molarity of the solution after electrolysis would be

Answer»

0.46 M
0.625 M
0.92 M
1.25 M

Solution :`Q=9.65 xx 3 xx60 xx60 = 104220 C`
`Ni^(@)+2e^(-) rarr Ni`
`2 xx 96500 C` deposit 1 mole of `Ni^(2+)`
`THEREFORE 104220 C` will deposit `Ni^(2+)`
`(1)/(2 xx96500) xx 104220 = 0.54 ` mole
ORIGINALLY 0.5 L of 2M sol. Contains `Ni^(2+)` =1 mole. Now 0.5 L will contain `Ni^(2+) =1 -0.54 =0.46` mole
Hence, molarity = 0.92 mol `L^(-1)`


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