1.

A current of strength 2.5 amp was passed through CuSO_(4) solution for 6 minutes 26 seconds. The amount of copper deposited is:- (Atomic weight of Cu=63.5) (1 faraday=96500 coulombs)

Answer»

0.3175 g
3.175 g
0.635 g
6.35 g

Solution :`Q=2.5xx386=96500C`
`2F(2xx96500C)` deposited `C u=63.5g`
`therefore`HENCE 965 C will deposited, Cu=0.3175gm.


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