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A current strength of 3.86 A was passed through molten Calcium oxide for 41 minutes and 40 seconds. The mass of Calcium in grams deposited at the cathode is (atomic mass of Ca is 40g/mol and 1F = 96500 C).

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Solution :`m = ZIT ""41 "min" 40 "SEC" = 2500 "seconds"`
`= (40 xx 3.86 xx 2500)/(2 xx 96500) "" Z = (m)/(n xx 96500) = 40/(2 xx 96500)`
` = 2g`.


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