1.

A curve passes through the point (0, -2) and at any point (x, y) of the curve, the product of the slope of its tangent and y-coordinate of the point is equal to the x-coordinate of the point. Find the equation of the curve.

Answer»

Given that the product of slope of tangent and y coordinate equals the x-coordinate i.e.,y \(\frac{dy}{dx}\) = x

We have ydy = xdx

⇒ ∫ydy = ∫xdx

⇒ y2/2 = x2/2 + c

For the curve passes through (0, -2), we get c = 2, 

Thus, the required particular solution is:-

∴ y2 = x2 + 4



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