InterviewSolution
Saved Bookmarks
| 1. |
A curve passes through the point (0, -2) and at any point (x, y) of the curve, the product of the slope of its tangent and y-coordinate of the point is equal to the x-coordinate of the point. Find the equation of the curve. |
|
Answer» Given that the product of slope of tangent and y coordinate equals the x-coordinate i.e.,y \(\frac{dy}{dx}\) = x We have ydy = xdx ⇒ ∫ydy = ∫xdx ⇒ y2/2 = x2/2 + c For the curve passes through (0, -2), we get c = 2, Thus, the required particular solution is:- ∴ y2 = x2 + 4 |
|