1.

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:y = cos x + C : y’+ sin x = 0

Answer»

Given y = cos x + C 

⇒ y' = \(\frac{d}{dx}\)(cos x + C) = – sin x 

Given, y’ + sinx = 0

sinx + sinx = 0 

LHS = RHS 

Hence y = cos x + C, is solution of given differential equation.



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