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Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:y = cos x + C : y’+ sin x = 0 |
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Answer» Given y = cos x + C ⇒ y' = \(\frac{d}{dx}\)(cos x + C) = – sin x Given, y’ + sinx = 0 sinx + sinx = 0 LHS = RHS Hence y = cos x + C, is solution of given differential equation. |
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