1.

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:y5= x2 + 2x + C : y’ – 2x – 2 = 0

Answer»

Given y = x2 + 2x + C

⇒ y' = \(\frac{d}{dx}\)(x2 + 2x + C = 2x + 2 

Given, y’ = 2x - 2 

= 2x + 2 – 2x – 2 = 0 

LHS = RHS 

Hence y = x2 + 2x + C, is solution of given differential equation



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