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A cyclist speeding at 4.5 km/h on a level road takes a sharp circular turn of radius 3 m without reducing the speed. The coefficient of static friction between the road and the tyres is 0.1. (i) Will he slip while taking the turn? (ii) Will he slip if his speed is 9 km/h? |
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Answer» SOLUTION :Frictional force PROVIDES the necessary CENTRIPETAL force. He will slip if the TURN is too sharp (i.e., too small a radius) or if his SPEED is too large. Maximum speed for not slipping is `v_("max")=sqrt(mu_(s)Rg)=sqrt(0.1xx3xx9.8)=1.71 m//s` (i) If `v=4.5 km//h=(5)/(4)m//s=1.25m//s,` he will not slip. (ii) If `v=9 km//h =(5)/(2) m//s=2.5m//s,` he will slip. |
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