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A cyclotron is operating at a frquency of `12xx10^6Hz`. Mass of deutron is `3.3 xx10^-19` coulomb. To accelerate deutrons the magnetic field isA. 0.016 teslaB. 0.16 teslaC. 16 teslaD. 1.6 tesla |
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Answer» Correct Answer - D `v =(q B)/(2 pi m)` `therefore B =(2 pi mv )/(q)` `=(2xx3.14xx3.3 xx10^-27xx12xx10^6)/(1.6xx10^-19)` `= 1.6 T`. |
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