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A cyclotron, when being used to accelerate protons (mass = 1.67 xx 10^(-27) kg, charge = 1.6 xx 10^(-19) C) has a magnetic field of (pi)/2 tesla applied normal to the plane of its does. What must be the value of the frequency of the applied alternating electric field to be used in it? |
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Answer» Solution :Here mass of protons `m = 1.67 xx 10^(-27)KG`, charge on a proton `q = +1.6 xx10^(-19) C`, magnetic field `B = pi/2 T`. `:.` FREQUENCY of applied alternating electric field `v = (QB)/(2 pi m) = (1.6 xx 10^(-19) xx (pi//2))/(2pi xx 1.67 xx 10^(-27)) = 2.4 xx 10^(7) HZ` . |
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