A cylinder containing one gram molecule of the gas was compressed adiabaticaly untill its tempertaure rose from `27^(@)C` to `97^(@)C`. Calculate the work done and heat produced in the gas `(gamma=1.5)`.

A cylinder containing one gram molecule of the gas was compressed adia

1.	A cylinder containing one gram molecule of the gas was compressed adiabaticaly untill its tempertaure rose from `27^(@)C` to `97^(@)C`. Calculate the work done and heat produced in the gas `(gamma=1.5)`.
Answer» Here, initial temperature, `T_(1)= 27^(@)C= 273+27= 300K` final temperature, `T_(2)= 97^(@)C= 273+97= 370K`. When a gas is compressed adiabatically, work done on gas is given by `W=R/((1-gamma))(T_(2)-T_(1))` `=(8.3xx(370-300))/(1-1.5)` `= -11.62xx10^(2)J` `:.` Heat produced, `H= (-W)/J= (11.62xx10^(2))/(4.2)= 276.7cal`.

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A cylinder containing one gram molecule of the gas was compressed adiabaticaly untill its tempertaure rose from `27^(@)C` to `97^(@)C`. Calculate the work done and heat produced in the gas `(gamma=1.5)`.

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