1.

A cylinder of compressed gas contains nitrogen and oxygen in the ratio 3:1 by mole. If the cylinder is known to contain 2.5xx10^(4)g of oxygen, what is the total mass of the gas mixture?

Answer»

Solution :NUMBER of moles of oxygen in the CYLINDER
`=("Mass in gram")/("Molecular mass in gram")=(2.5xx10^(4))/(32)`
=781.25
`therefore` Number of moles of `N_(2)=3xx781.25=2343.75`
Mass of nitrogen in the cylinder `=2343.75xx28`
=65625g
`=6.5625xx10^(4)G`
Total mass of the gas in the cylinder
`=2.5xx10^(4)+6.5625xx10^(4)=9.0625xx10^(4)g`


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