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A cylinder of fixed capacity 44.8 litre contains helium gas at standard temperature and pressure. What is the amount of heat needed to raise the temperature of the gas in the cylinder by `15.0^(@) C ? [R = 8.31 J mol^(-1) K(-1)]` |
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Answer» It is known that one mole of any ideal gas at NTP occupies a volume of 22.4 litre. As the cylinder has a fixed capacity of 44.8 litre, it must contain 2 moles of helium at NTP. For Helium (momoatomic gas), `C_(upsilon) = 3/2 R` `:.` Heat required `=n` umber o f moles `xx` molar sp. `h e a t xx r i s e i n t e m p e r a t u r e` `Q=2 xx 3/2 R xx 15 = 45 r = 45 xx 8.31 J` `= 373.95 J`. |
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