1.

A cylindrical piece of Mg is 10 cm long and has a diameter of 8 cm. The density of Magnesium is 0.7 gm//cm^(3). How many atoms does piece of Mg contain. [N_(A) = 6 xx 10^(23)] [Divide your answer by 22 xx 10^(23) ]

Answer»


Solution :Volume of cylindrical piece `= pi r^(2)L`
`= pi xx ((8)/(2))^(2) xx 10`
`= (22)/(7) xx 4 xx 4 xx 10`
`= ((22)/(7) xx 160) cm^(3)`
Mass of piece `= (0.7 xx (22)/(7) xx 160) cm^(3)`
`= (22 xx 16) gm`
Atoms of `Mg = ((22 xx 16)/(24)) N_(A) RARR (44)/(3) N_(A)`
`= (44)/(3) xx 6 xx 10^(23)`
`= (88 xx 10^(23))/(22 xx 10^(23)) = 4`


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