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A cylindrical rod of length l=2m & density (rho)/(2) floats vertically in a liquid of density rho as shown in Fig (a) (a) Show that it performs SHM when pulled slightly up & released & find its time period. Neglect change in liquid level. (b) Find the time taken by the rod to completely immerse when released from position showm in (b). Assume that it remains vertical throughout its its motion ("take" g=pi^(2)m//s^(2)) |
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Answer» `F_(R)=-[Axx2xx(rho)/(2)xxg-A(1-x)rhog]` `F_(R)=-[Arhog-Arhog+Axrhog]` `F_(R)=-Arhogx` So `K=Arhog` HENCE `T=2pisqrt((m)/(k))IMPLIES" " T=2pisqrt((Arho)/(Arhog)) implies T=2pisqrt((1)/(g))implies T=2sec`
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