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A cyslist is traveilling on a circular section of highway of radius 2500 ft at the speed of 60 mile/h. The cyclist suddenly applies the brakes causing the bicycle to slow down at constant rate. Knowing that after 8 second,the speed has been reduced to 45 mile/h. The acceleration of the bicyle immediately after the breakes have been applied. isA. `2 ft//s^(2)`B. `4.14 ft//s^(2)`C. `3.10 ft//s^(2)`D. `2.75 ft^(2)//s` |
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Answer» (b) Tangential acceleration `=a_(t)=(v_(t)-v_(i))/(t)=((45-60)/(8))((22)/(15))=-(11)/(4)ft//s^(2)` The radial acceleration is `a_(n)=(v^(2))/(r)=(60xx(22)/(15))^(2)/(2500)=3.1` `:." " a=sqrt(a_(n)^(2)+a_(t)^(2))=4.14 ft//s^(2)` |
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