1.

A D.C. motor working on 200V have initial current of 5A but when it attained maximum velocity, the current obtained is 3A. What will be its Back emf ?

Answer»

0V
80 V
120 V
200 V

Solution :`R=E/I=200/5=40 Omega`
Now `I=(E-EPSILON)/R rArr 3= (200-epsilon)/40`
`therefore120=200-epsilon`
`THEREFORE epsilon` =80 V


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