1.

A dam provides water fall for a power house 300 m below. The catchment area of 10^(10)m^(2) has annual rainfall of 0.6 m. 25%+ 15% + 10% wateris lost due to different reasons. Then,

Answer»

mass of water FALL is `3XX10^(12)`kg
work DONE by water fall is `8.82xx10^(15)`J
work done by water fail is `8.11xx10^(10) `J
average power OUTPUT of the station is 200 MW

Solution :`m=v rho xx (50)/(100)= A L rho xx 1/2 = (10^(10)xx0.6 xx10^(3))/(2)=3xx10^(12)`kg
`W=3xx10^(12) xx 9.8xx300=9xx9.8=8.82xx10^(15)`
`:.` (A) & (B)


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