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A Daniel cell constructed in the laboratory. The voltage observed was `0.9V` instead of `1.10V` of the standard cell. A possible explanation isA. Molar ratio of `Zn^(+2),Cu^(2+)`is `2:1`B. The Zn electrode has thrice the surface of Cu electrodeC. `[Zn^(2+)]lt[Cu^(2+)]`D. `[Zn^(2+)]gt[Cu^(2+)]` |
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Answer» Correct Answer - D `E_(cell)=E_(cell)^(@)-(0.059)/(n)log.([Zn^(2+)])/([Cu^(2+)])` `E_(cell) " decrease indicates" [Zn^(2+)]gt[Cu^(2+)]` |
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