InterviewSolution
Saved Bookmarks
| 1. |
`wedge^(@)._(m)` for `CaCl_(2)` and `MgSO_(4)` from the given data. `lambda_(Ca^(2+))^(@)=119.0S cm^(2)mol^(-1)` ltbr. `lambda_(Cl^(c-))^(@)=76.3S cm^(2)mol^(-1)` `lambda_(Mg^(2+))^(@)=106.0S cm^(2)mol^(-1)` `lambda_(SO_(4)^(2-))^(@)=160.0 cm^(2)mol^(-1)` |
|
Answer» `Lambda_(m)^(0)CaCl_(2)=lambda_(Ca^(2+))^(0)+2lambda_(Cl^(-))^(0)` `=119+"2 x 76.3"=271.6S cm^(2)mol^(-1)` `Lambda_(m)^(0)MgSO_(4)=lambda_(Mg^(2+))^(0)+lambda_(SO_(4)^(2-))^(0)` `=106+160="266 S cm"^(2)mol^(-1)` |
|