1.

`wedge^(@)._(m)` for `CaCl_(2)` and `MgSO_(4)` from the given data. `lambda_(Ca^(2+))^(@)=119.0S cm^(2)mol^(-1)` ltbr. `lambda_(Cl^(c-))^(@)=76.3S cm^(2)mol^(-1)` `lambda_(Mg^(2+))^(@)=106.0S cm^(2)mol^(-1)` `lambda_(SO_(4)^(2-))^(@)=160.0 cm^(2)mol^(-1)`

Answer» `Lambda_(m)^(0)CaCl_(2)=lambda_(Ca^(2+))^(0)+2lambda_(Cl^(-))^(0)`
`=119+"2 x 76.3"=271.6S cm^(2)mol^(-1)`
`Lambda_(m)^(0)MgSO_(4)=lambda_(Mg^(2+))^(0)+lambda_(SO_(4)^(2-))^(0)`
`=106+160="266 S cm"^(2)mol^(-1)`


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