1.

A Dealer Bought Two Tables For Rs.3120. He Sold One Of Them At A Loss Of 15% And The Other At A Gain Of 36%. . Then, He Found That Each Table Was Sold For The Same Price. Find The Cost Price Of Each Table.

Answer»

Given that the selling price is same for both the tables.

LET the C.P of 1 table be x

Then the C.P of the other table be = RS.3120-x

Loss on the first table = 15%

THEREFORE, S.P = 85x10

= 0.85x

Gain on the second table = 36%

136(3120-x)

Since both the tables have the same S.P

2.21x = 4243.20

= x= 1920

The cost price of the table is Rs.1920

The cost price of the other table is Rs.(3120-1920) = Rs.1200

Given that the selling price is same for both the tables.

Let the C.P of 1 table be x

Then the C.P of the other table be = Rs.3120-x

Loss on the first table = 15%

Therefore, S.P = 85x10

= 0.85x

Gain on the second table = 36%

136(3120-x)

Since both the tables have the same S.P

2.21x = 4243.20

= x= 1920

The cost price of the table is Rs.1920

The cost price of the other table is Rs.(3120-1920) = Rs.1200



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