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A Dealer Bought Two Tables For Rs.3120. He Sold One Of Them At A Loss Of 15% And The Other At A Gain Of 36%. . Then, He Found That Each Table Was Sold For The Same Price. Find The Cost Price Of Each Table. |
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Answer» Given that the selling price is same for both the tables. LET the C.P of 1 table be x Then the C.P of the other table be = RS.3120-x Loss on the first table = 15% THEREFORE, S.P = 85x10 = 0.85x Gain on the second table = 36% 136(3120-x) Since both the tables have the same S.P 2.21x = 4243.20 = x= 1920 The cost price of the table is Rs.1920 The cost price of the other table is Rs.(3120-1920) = Rs.1200 Given that the selling price is same for both the tables. Let the C.P of 1 table be x Then the C.P of the other table be = Rs.3120-x Loss on the first table = 15% Therefore, S.P = 85x10 = 0.85x Gain on the second table = 36% 136(3120-x) Since both the tables have the same S.P 2.21x = 4243.20 = x= 1920 The cost price of the table is Rs.1920 The cost price of the other table is Rs.(3120-1920) = Rs.1200 |
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