1.

(a) Define the following terms : (i) Ideal solution (ii) Azeotrope (iii) Osmotic pressure (b) A solution of glucose (C_(6)H_(12)O_(6))in water is labelled as 10% by weight. What would be the molality of the solution ? (Molar mass of glucose = 180 g mol^(-1))

Answer»

SOLUTION :(a) (i) IDEAL solution : Refer S.A. T.Q. 7 (ii).
(ii) Azeotrope : A liquid mixture which distills at constant temperature without under going any changes in composition is called Azeotrope.
(iii) Osmotic presslll.e : Refer V.S.A.T.Q. 2. (b) Given MOLECULAR mass of glucose = 180 G `mol^(-1)` % by weight = 10%
`m=(100-WT%)/((100-wt%)xx"molecular wt. solute")`
or `m = (wxx1000)/(MxxW)`
`m=(1000xx10)/((100-10)xx180)`
`=(1000)/(90xx180)`
m = 0.617 m


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