1.

A `DeltaABC` can be constructed in which `angleB = 60^(@), angleC = 45^(@) and AB + BC + CA = 12 cm`.

Answer» Correct Answer - 1
we know that sum of angles of a triangle is `180^(@)`
`:. angleA + angleB+ angleC = 180^(@)`
Here, `angleB + angleC = 60^(@) + 45^(@) = 105^(@) lt 180^(@)`,
Thus, `DeltaABC` with given conditions can be constructed.


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