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A `DeltaABC` can be constructed in which `angleB = 60^(@), angleC = 45^(@) and AB + BC + CA = 12 cm`. |
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Answer» Correct Answer - 1 we know that sum of angles of a triangle is `180^(@)` `:. angleA + angleB+ angleC = 180^(@)` Here, `angleB + angleC = 60^(@) + 45^(@) = 105^(@) lt 180^(@)`, Thus, `DeltaABC` with given conditions can be constructed. |
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