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To divide a line segment AB in the ratio 5:7, first a ray AX is drawn, so that `/_BAX` is an acute angle and then at equal distances point are marked on the ray AX such that the minimum number of these points isA. 8B. 10C. 11D. 12 |
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Answer» Correct Answer - D (d) We know that to divide a line segment AB in the ratio m:n, first draw a ray AX which makes an acute angle `angleBAX`, then marked m+n points at equal distance. Here, m=5,n=7 So, minimum number of these points =m+n=5+7=12 |
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