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(a) Derie an expression for the force between two long parallel current carryng condcutors. (b) Use this expression to define SI unit of current. (c ) A long straight wire AB carries a current I. A proton P travels with a speed v, parallel to the wire, at a distance d from it in a direction oppositeto the current as shown in the fig. What is the force experienced by the proton and what is its direction? |
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Answer» Solution :(c) The magnetic field produced due to long, straight current carrying wire AB at the position of proton is `B = (mu_0 I)/(2 pi d)` and it is directed perpendicular to the plane of paper pointing inward. The proton q = +E moving with a velocity v in a direction opposite to the current experience a force `F = qvB = EV CDOT (mu_0 I)/(2 pi d) = (mu_0 evI)/(2 pi d)` In accordance with Fleming.s left hand rule the force is repulsive in nature as shown in fig. Thus, the force is perpendicular to direciton of motion of proton directed AWAY from the current carrying conductor. 
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