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(a) Derive the expression for the torque on a rectangular current carrying loop suspended in a uniform magnetic field. (b) A proton and a deuteron having equal momenta enter in a region of uniform magnetic field at right angle to the direction of the field. Depict their trajectories in the field. |
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Answer» SOLUTION :(b) When a charged particle of charge .q. and momentum .p. enters in a region of uniform magnetic field `vecB` at right angle to the direction of the field, it describe a circular trajectory of radius `r = p/(qB)` As proton and deuteron have same charge and EQUAL momenta, hence both will revolve in EXACTLY the same circular path as shown FIG. 
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