A diamond worth Rs 640000 breaks into two pices whose weights are in the ratio 5:3. if the value of the diamond varies directly with square of its weight, then find loss incurred due to breakage (in Rs).A. 320000B. 300000C. 360000D. none of these

A diamond worth Rs 640000 breaks into two pices whose weights are in t

1.	A diamond worth Rs 640000 breaks into two pices whose weights are in the ratio 5:3. if the value of the diamond varies directly with square of its weight, then find loss incurred due to breakage (in Rs).A. 320000B. 300000C. 360000D. none of these
Answer» Correct Answer - B (i) diamond is of 8 parts. `therefore64x^(2)=640000` (ii) `(25x^(2)+9x^(2))=34x^(2)` is the value of diamond, when it is broken into the parts whose weights are in the ratio of 5:3 (iiI) Loss incurred `=64x^(2)-34x^(2)=30x^(2)`

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A diamond worth Rs 640000 breaks into two pices whose weights are in the ratio 5:3. if the value of the diamond varies directly with square of its weight, then find loss incurred due to breakage (in Rs).A. 320000B. 300000C. 360000D. none of these

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