1.

A diatomic gas which has initial volume of 10 liter is isothermally compressed to 1//15^(th) of its original volume where initial pressure is 10^(5) Pascal. If temperature is 27^(@)C then find the work done by gas

Answer»

`-2.71xx10^(3)J`
`2.70xx10^(3)J`
`-1.35xx10^(3)J`
`1.35xx10^(3)J`

Solution :`w=nRTln((v_(2))/(v_(1)))`
`w=P_(0)V_(0)ln ((v_(2))/(v_(1)))`
`w=10^(5)xx10xx10^(-3)ln ((1)/(15))`
`w=- 2.70 xx10^(3)J`


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