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A diatomic gas which has initial volume of 10 liter is isothermally compressed to 1//15^(th) of its original volume where initial pressure is 10^(5) Pascal. If temperature is 27^(@)C then find the work done by gas |
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Answer» `-2.71xx10^(3)J` `w=P_(0)V_(0)ln ((v_(2))/(v_(1)))` `w=10^(5)xx10xx10^(-3)ln ((1)/(15))` `w=- 2.70 xx10^(3)J` |
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