1.

A dice is rolled 600 times and the occurrence of the outcomes 1, 2, 3, 4, 5 and 6 are given below :Outcome123456Frequency2003012010050100The probability of getting a prime number isA. \(\frac{1}{3}\)B. \(\frac{2}{3}\)C. \(\frac{49}{60}\)D. \(\frac{39}{125}\)

Answer»

Correct answer is A.

Total trials = 600

No. Of getting prime number = 30 + 120 + 50 = 200

Let E be the event of getting a prime number so,

\(P(E)=\frac{200}{600}=\frac{2}{6}=\frac{1}{3}\)



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