A dice is thrown six times, it being known that each time a differentdigit is shown. The probability that a sum of 12 will b e obtained in thefirst three throws is`5//24`b. `25//216`c. `3//20`d. `1//12`A. `(5)/(24)`B. `(25)/(216)`C. `(3)/(20)`D. `(1)/(12)`

A dice is thrown six times, it being known that each time a differentd

1.	A dice is thrown six times, it being known that each time a differentdigit is shown. The probability that a sum of 12 will b e obtained in thefirst three throws is`5//24`b. `25//216`c. `3//20`d. `1//12`A. `(5)/(24)`B. `(25)/(216)`C. `(3)/(20)`D. `(1)/(12)`
Answer» Correct Answer - C Since it is known that each time a different digit appears, total number of cases is `6!` The sum in the first three throws is 12 if we get (1, 5, 6), (2, 4, 6) or (3, 4, 5) in any order. So, number of cases for first three throws = `3 xx 3!` ways. `therefore` Number of favourable cases = `3 xx 3! xx 3!` `therefore` Required probability = `(3 xx 3! xx 3!)/(6!) = (3)/(20)`

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A dice is thrown six times, it being known that each time a differentdigit is shown. The probability that a sum of 12 will b e obtained in thefirst three throws is`5//24`b. `25//216`c. `3//20`d. `1//12`A. `(5)/(24)`B. `(25)/(216)`C. `(3)/(20)`D. `(1)/(12)`

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