A dice is thrown twice, what is the probability of getting two 3’s?(a) \(\frac {1}{66}\)(b) \(\frac {1}{16}\)(c) \(\frac {1}{36}\)(d) \(\frac {1}{36}\)The question was posed to me in final exam.I'd like to ask this question from Probability topic in portion Probability of Mathematics – Class 12

A dice is thrown twice, what is the probability of getting two 3’s?(

1.	A dice is thrown twice, what is the probability of getting two 3’s?(a) \(\frac {1}{66}\)(b) \(\frac {1}{16}\)(c) \(\frac {1}{36}\)(d) \(\frac {1}{36}\)The question was posed to me in final exam.I'd like to ask this question from Probability topic in portion Probability of Mathematics – Class 12
Answer» The correct OPTION is (d) \(\frac {1}{36}\) To ELABORATE: PROBABILITY of GETTING 3 in the first throw = \(\frac {1}{6}\) Probability of getting of 3 in the second throw = \(\frac {1}{6}\) Total probability = \(\frac {1}{6} \times \frac {1}{6} = \frac {1}{36}\)

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