A die is thrown. Find the probability of getting a multiple of 3

1.	A die is thrown. Find the probability of getting a multiple of 3
Answer» We know that, Probability of occurrence of an event = \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\) As 3, 6 are multiples up to 6, so the desired outcomes are 3, 6, and total outcomes are 1, 2, 3, 4, 5, 6 Therefore, total no. of outcomes are 6, and total no. of desired outcomes are 2 Probability of getting multiple of 3 = \(\frac{2}{6}\) = \(\frac{1}{3}\) Conclusion: Probability of getting multiple of 3 when die is thrown is \(\frac{1}{3}\)

Answer»

We know that,

Probability of occurrence of an event

= \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\)

As 3, 6 are multiples up to 6, so the desired outcomes are 3, 6, and total outcomes are 1, 2, 3, 4, 5, 6

Therefore, total no. of outcomes are 6, and total no. of desired outcomes are 2

Probability of getting multiple of 3

= \(\frac{2}{6}\)

= \(\frac{1}{3}\)

Conclusion: Probability of getting multiple of 3 when die is thrown is \(\frac{1}{3}\)

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A die is thrown. Find the probability of getting a multiple of 3

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