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A die is thrown. Find the probability of getting:(i) a prime number(ii) 2 or 4(iii) a multiple of 2 or 3 |
Answer» Given: A die is thrown. The total number of outcomes is six, n (S) = 6 By using the formula, P (E) = favourable outcomes / total possible outcomes (i) Let E be the event of getting a prime number E = {2, 3, 5} n (E) = 3 P (E) = n (E) / n (S) = 3 / 6 = 1/2 (ii) Let E be the event of getting 2 or 4 E = {2, 4} n (E) = 2 P (E) = n (E) / n (S) = 2 / 6 = 1/3 (iii) Let E be the event of getting a multiple of 2 or 3 E = {2, 3, 4, 6} n (E) = 4 P (E) = n (E) / n (S) = 4 / 6 = 2/3 |
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