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A die is thrown once. Find the probability of getting a multiple of 3. |
Answer» When a die is thrown, all possible outcomes are 1,2,3,4,5,6. Total number of possible outcomes = 6. (i) Let `E_(1)` be the event of getting an even prime number. Then, the favourable outcomes is 2 only. Number of favourable outcomes = 1. `:. ` P(getting an even prime number ) ` = P(E_(1)) = 1/6.` (ii) Let `E_(2)` be the event of getting a multiple of 3. Then, the favourable outcomes are 3 and 6. Number of favourable outcomes = 2. `:. ` P(getting a multiple of 3 ) ` = P(E_(2)) = 2/6 = 1/3`. |
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