A die is thrown once. The probebility of getting a prime number isA.

1.	A die is thrown once. The probebility of getting a prime number isA. \(\frac{2}3\)B. \(\frac{1}3\)C. \(\frac{1}2\)D.\(\frac{1}6\)
Answer» Total numbers of elementary events are: 6 Let E be the event of getting a prime number Favorable events are: 2, 3, 5 Numbers of favorable events are = 3 P (prime number) = P (E) = \(\frac{3}6\) = \(\frac{1}2\)

A die is thrown once. The probebility of getting a prime number isA. \(\frac{2}3\)B. \(\frac{1}3\)C. \(\frac{1}2\)D.\(\frac{1}6\)

Answer»

Total numbers of elementary events are: 6

Let E be the event of getting a prime number

Favorable events are: 2, 3, 5

Numbers of favorable events are = 3

P (prime number) = P (E) = \(\frac{3}6\) = \(\frac{1}2\)

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A die is thrown once. The probebility of getting a prime number isA. \(\frac{2}3\)B. \(\frac{1}3\)C. \(\frac{1}2\)D.\(\frac{1}6\)

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