A dielectric slab fills the space between the square plates of a parallel-plate capacitor. The side of each plate of the capacitor is L. The magnitude of the bound charges on the slab is 75% of the magnitude of the free charge on the plates. The capacitance is 480muF and the maximum charge that can be stored on the capacitor is 240epsilon_(0)L^(2)E_("max"), where E_("max") is the breakdown strength of the medium:

A dielectric slab fills the space between the square plates of a paral

1.	A dielectric slab fills the space between the square plates of a parallel-plate capacitor. The side of each plate of the capacitor is L. The magnitude of the bound charges on the slab is 75% of the magnitude of the free charge on the plates. The capacitance is 480muF and the maximum charge that can be stored on the capacitor is 240epsilon_(0)L^(2)E_("max"), where E_("max") is the breakdown strength of the medium:
Answer» The dielectric constant for the dielectric SLAB is 4 Without the dielectric, the capacitance of the capacitor WOULD be `360muF` The plate area is `60L^(2)` If the dielectric slab is having the same area as that of the capacitor plate but the WIDTH is half the SEPARATION between plates of capacitor, the capacitance would be `192muF` Answer :A::C::D

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